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The range() method returns an immutable sequence of numbers between the given start integer to the stop integer.
Tóm lược đại ý quan trọng trong bài
print(list(range(6)))
# Output: [0, 1, 2, 3, 4, 5]
range() constructor has two forms of definition:
range(stop)
range(start, stop[, step])
range() takes mainly three arguments having the same use in both definitions:
range() returns an immutable sequence object of numbers depending upon the definitions used:
The return value is calculated by the following formula with the given constraints:
r[n] = start + step*n (for both positive and negative step)
where, n >=0 and r[n] = 0 and r[n] > stop (for negative step)
# empty range
print(list(range(0))) # using range(stop)
print(list(range(10))) # using range(start, stop)
print(list(range(1, 10)))
Output
[]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
Note: We’ve converted the range to a Python list, as range() returns a generator-like object that only prints the output on demand.
However, the range object returned by the range constructor can also be accessed by its index. It supports both positive and negative indices.
You can access the range object by index as:
rangeObject[index]
start = 2
stop = 14
step = 2
print(list(range(start, stop, step)))
Output
[2, 4, 6, 8, 10, 12]
start = 2
stop = -14
step = -2
print(list(range(start, stop, step)))
# value constraint not met
print(list(range(start, 14, step)))
Output
[2, 0, -2, -4, -6, -8, -10, -12]
[]
PythonServer Side ProgrammingProgramming
Python can handle any requirement in data manipulation through its wide variety of libraries and methods. When we need to generate all the numbers between a pair of given numbers, we can use python’s inbuilt functions as well as some of the libraries. This article describes such approaches.
The range() function returns a sequence of numbers, starting from 0 by default, and increments by 1 ending at a specified number. We can of curse change the starting, ending as well as increment steps to suit our need.
Live Demo
def getnums(s, e,i):
return list(range(s, e,i))
# Driver Code
start, end, intval = -3, 6,2
print(getnums(start, end,intval))
Running the above code gives us the following result −
[-3, -1, 1, 3, 5]
The random module can also generate a random number between in a similar way as above. It involves calling the randrange method and supplying the parameters for start, end and interval values.
Live Demo
import random
def getnums(s, e,i):
return (random.randrange(s, e,i))
# Driver Code
start, end, intval = 3, 16,2
print(getnums(start, end,intval))
Running the above code gives us the following result −
7
The numpy library also provides a very wide range of functions for these requirements. We use arrange function which will also take the required parameters and give the output as a list.
Live Demo
import numpy as np
def getnums(s, e,i):
return (np.arange(s, e,i))
# Driver Code
start, end, intval = 3, 16,2
print(getnums(start, end,intval))
Running the above code gives us the following result −
[ 3 5 7 9 11 13 15]
Published on 04-May-2020 12:57:48
Examples of how to create a list of numbers in python using list comprehensions or built-in functions list():
To create a list of integers between 0 and N, a solution is to use the range(N) function:
>>> l = [i for i in range(10)]
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
To create a list of integers between N and M (with M>N), the function range() can still be used:
>>> l = [i for i in range(25,35)]
>>> l
[25, 26, 27, 28, 29, 30, 31, 32, 33, 34]
>>> l = list(range(25,35))
>>> l
[25, 26, 27, 28, 29, 30, 31, 32, 33, 34]
To create a list of floats between (N,M) with a given step, a solution is to use the numpy function called arange:
>>> import numpy as np
>>> l = [i for i in np.arange(2,8,0.5)]
>>> l
[2.0, 2.5, 3.0, 3.5, 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0, 7.5]
>>> l = list(np.arange(2,8,0.5))
>>> l
[2.0, 2.5, 3.0, 3.5, 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0, 7.5]
To create a list of floats between (N,M) with a given number of elementsa solution is to use the numpy function linspace:
>>> import numpy as np
>>> l = [i for i in np.linspace(12,16,8)]
>>> l
[12.0, 12.571428571428571, 13.142857142857142, 13.714285714285714, 14.285714285714285, 14.857142857142858, 15.428571428571429, 16.0]
>>> l = list(np.linspace(12,16,8))
>>> l
[12.0, 12.571428571428571, 13.142857142857142, 13.714285714285714, 14.285714285714285, 14.857142857142858, 15.428571428571429, 16.0]
The python function randint can be used to generate a random integer in a chosen interval [a,b]:
>>> import random
>>> random.randint(0,10)
7
>>> random.randint(0,10)
0
A list of random numbers can be then created using python list comprehension approach:
>>> l = [random.randint(0,10) for i in range(5)]
>>> l
[4, 9, 8, 4, 5]
Another solution is to use randrange function (except that can specify a step if you need):
>>> l = [random.randrange(0,10) for i in range(5)]
>>> l
[1, 7, 4, 3, 1]
>>> l = [random.randrange(0,10,2) for i in range(5)]
>>> l
[2, 4, 4, 6, 0]
A third solution is to create a list of random numbers with no repetition, is to use random.sample function
>>> l = random.sample(range(1,100), 10)
>>> l
[89, 56, 87, 51, 46, 25, 52, 44, 10, 32]
In Pythons <= 3.4 you can, as others suggested, use list(range(10)) in order to make a list out of a range (In general, any iterable).
Another alternative, introduced in Python 3.5 with its unpacking generalizations, is by using * in a list literal []:
>>> r = range(10)
>>> l = [*r]
>>> print(l)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Though this is equivalent to list(r), it’s literal syntax and the fact that no function call is involved does let it execute faster. It’s also less characters, if you need to code golf 🙂
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